🔹 Java is Pass-by-Value: What It Really Means

Have you ever wondered why modifying a method parameter doesn’t always change the original variable in Java?

This is because Java is always pass-by-value. Let’s break it down.

1️⃣ What Does Pass-by-Value Mean?

When you pass a variable to a method…


This content originally appeared on DEV Community and was authored by Mohamad mhana

Have you ever wondered why modifying a method parameter doesn’t always change the original variable in Java?

This is because Java is always pass-by-value. Let’s break it down.

1️⃣ What Does Pass-by-Value Mean?

When you pass a variable to a method, Java makes a copy of the value and sends it to the method.

Primitive types (int, double, boolean) → method works on the copy, original stays unchanged.

Objects → method receives a copy of the reference. You can modify the object’s contents, but reassigning the reference won’t affect the original object.

Think of it like sending a photocopy of a key. You can open the door (modify the object), but replacing the key (reassigning the reference) won’t change the original.

2️⃣ Example 1: Primitives

int x = 10;
modifyPrimitive(x);
System.out.println(x); // Output: 10

void modifyPrimitive(int number) {
    number = 20;
}

✅ Explanation: number is a copy of x, so changing it inside the method does not affect x.
✅ Enforces: Understanding of primitive types and variable scope.

3️⃣ Example 2: Objects

Person person = new Person("Mohammed");
modifyObject(person);
System.out.println(person.name); // Output: Ali

void modifyObject(Person p) {
    p.name = "Ali"; // Modifies the object itself
}

✅ Explanation: Method gets a copy of the reference, so you can modify the object’s state.
✅ Enforces: Understanding objects vs references.

4️⃣ Example 3: Reassigning Objects

Person person = new Person("Mohammed");
reassignObject(person);
System.out.println(person.name); // Output: Mohammed

void reassignObject(Person p) {
    p = new Person("Ali"); // Only reassigns inside method
}

✅ Explanation: Reassigning the reference does not affect the original object.
✅ Enforces: Understanding pass-by-value vs pass-by-reference confusion.

5️⃣ Key Takeaways

Everything in Java is pass-by-value.

Primitives: method gets a copy → original value unchanged.

Objects: method gets a copy of the reference → can modify object contents but not the original reference.

Knowing this prevents bugs and confusion when passing variables to methods.

Have you ever been confused why modifying an object in a method sometimes works and sometimes doesn’t?

Can you think of a scenario where misunderstanding pass-by-value could break your code?

Share your thoughts in the comments! 🚀

📚 Resources:

Baeldung - Java Pass by value

GeeksforGeeks - Java is always Pass by Value


This content originally appeared on DEV Community and was authored by Mohamad mhana


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