⚡ Two Pointer Technique

Ever spent hours writing nested loops to solve simple array or string problems, only to feel it’s slow and messy?

The Two Pointer Technique is a game-changer. It’s a powerful strategy to traverse arrays, lists, or strings efficiently using two markers…


This content originally appeared on DEV Community and was authored by Mohammed mhanna

Ever spent hours writing nested loops to solve simple array or string problems, only to feel it’s slow and messy?

The Two Pointer Technique is a game-changer. It’s a powerful strategy to traverse arrays, lists, or strings efficiently using two markers (pointers), reducing time complexity and improving code readability.

By the end of this post, you’ll know:

What the Two Pointer Technique is

How it works step by step

Real-world examples in Java

Common pitfalls to avoid

Practice challenges to master it

🌱 What Is the Two Pointer Technique?

The Two Pointer Technique uses two indices to iterate over data structures:

Opposite ends: One pointer at the start, one at the end

Same start: Slow and fast pointers moving at different speeds

✅ Ideal for sorted arrays, strings, and problems that require comparison or condition checking.

🛠 How It Works: Step by Step
1️⃣ Opposite Ends

Move pointers toward each other based on conditions.

Common for: finding pairs with a target sum, checking palindromes.

2️⃣ Same End (Slow & Fast)

Slow pointer moves step by step

Fast pointer moves faster

Detect duplicates, cycles in lists, or sliding window problems

3️⃣ Adjust Pointers Dynamically

If current condition < target → move left/slow forward

If current condition > target → move right/fast backward

Stop when pointers meet or satisfy problem condition

💡 Examples in Java
Example 1: Reverse an Array

int left = 0, right = arr.length - 1;
while(left < right){
    int temp = arr[left];
    arr[left] = arr[right];
    arr[right] = temp;
    left++; right--;
}

✅ Enforcement: In-place reversal saves memory and time.

Example 2: Pair With Target Sum

int left = 0, right = arr.length - 1;
while(left < right){
    int sum = arr[left] + arr[right];
    if(sum == target){ System.out.println(arr[left] + ", " + arr[right]); break; }
    else if(sum < target) left++; else right--;
}

✅ Enforcement: Linear time solution instead of nested loops.

Example 3: Remove Duplicates from Sorted Array

int i = 0;
for(int j = 1; j < arr.length; j++){
    if(arr[j] != arr[i]){
        i++;
        arr[i] = arr[j];
    }
}

✅ Enforcement: In-place modification reduces memory usage.

🌍 Real-World Applications

Palindrome check in strings

Two-sum problems in finance, scoring apps

Sliding window problems: max/min in a range

Cycle detection in linked lists

⚠️ Common Pitfalls & Mistakes

❌ Using Two Pointers on unsorted arrays without sorting first

❌ Moving pointers incorrectly → infinite loops or missed elements

❌ Using nested loops when two pointers suffice

❌ Ignoring boundary conditions (array length, empty arrays)

✅ Tip: Always visualize the pointer movement before coding.

🧩 Practice Challenges

Check if a string is a palindrome using two pointers.

Merge two sorted arrays efficiently.

Find all triplets in an array with a given sum.

Detect a cycle in a linked list (slow & fast pointers).

Sliding window: Find max sum of size k subarrays.

📚 Resources to Level Up

GeeksforGeeks: Two Pointer Technique

LeetCode: Two Pointer Problems

Java Arrays & Collections

🎯 Takeaway

The Two Pointer Technique is your secret weapon for solving array and string problems efficiently. It improves performance, reduces complexity, and makes your code cleaner and more readable.

💬 Engagement Questions:

Which problem did two pointers help you solve the most?

Can you think of a scenario where this technique would save time in your project?

Have you tried slow & fast pointers for linked lists yet?

Drop your thoughts in the comments — let’s discuss and learn together! 🚀


This content originally appeared on DEV Community and was authored by Mohammed mhanna


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