This content originally appeared on DEV Community and was authored by Yogesh Chavan
Take a look at the below code:
const promise = new Promise((resolve, reject) => {
resolve();
});
promise
.then(() => {
console.log('first');
})
.then(() => {
console.log('second');
})
.then(() => {
console.log('third');
})
.catch((error) => {
console.log('error', error);
});
If you execute the above code, you'll see the following output:
As you know each .then handler will be executed one after the another and the value returned from the previous .then handler is passed to the next .then handler so we get the output of the above code as:
first
second
third
which is as expected.
But now, take a look at the below code:
const promise = new Promise((resolve, reject) => {
resolve();
});
promise
.then(() => {
console.log('first');
})
.then(() => {
setTimeout(() => {
console.log('second');
}, 2000);
})
.then(() => {
setTimeout(() => {
console.log('third');
}, 1000);
});
If you execute the above code you will see the following output:
We're getting the output as:
first
third
second
In the above code, the second .then handler has a setTimeout function call with 2000 milliseconds(2 seconds) as the timeout so it will not be executed immediately, but the third .then will be executed before the second .then handler as it has a 1000 millisecond(1 second) timeout.
Therefore, we're seeing first printed immediately and after 1 second, third will be printed and after 2 seconds second will be printed.
So If any .then handler is making an API call or doing some long-running operation then that .then handler function might not be executed immediately but the next scheduled .then will be executed.
When you attach multiple
.thenhandlers, it’s not guaranteed that each.thenhandler will be called only after the previous.thenhandler finishes if there is additional asynchronous code inside the handler.
There is a way to fix this default behavior.
We can return a new promise from the second .then handler and only call resolve or reject once we are done with our API call or any other long-running operation.
This will guarantee that the next .then will always be executed after the previous one has finished.
This is because when we call a promise, the Promise will wait until we explicitly call resolve or reject inside the promise.
The following is the code that will maintain the order sequence:
const promise = new Promise((resolve, reject) => {
resolve();
});
promise
.then(() => {
console.log('first');
})
.then(() => {
return new Promise((resolve, reject) => {
setTimeout(() => {
console.log('second');
resolve();
}, 2000);
});
})
.then(() => {
setTimeout(() => {
console.log('third');
}, 1000);
});
As you can see, we're returning a promise from the second .then handler so the next .then handler will be executed only if the second .then handler resolves.
If you execute the above code you will see the following output:
As you can see now, each .then handle is executed only after the previous one is finished executed.
That's it about this article.
Thanks for reading!
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This content originally appeared on DEV Community and was authored by Yogesh Chavan
Yogesh Chavan | Sciencx (2021-06-22T08:37:49+00:00) The Most Important Thing You Don’t Know About Promises. Retrieved from https://www.scien.cx/2021/06/22/the-most-important-thing-you-dont-know-about-promises/
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