This content originally appeared on DEV Community and was authored by Falak
$valOne variable has string type value and $valTwo variable has original value. I calculated them and did not find error as I excepted.
$valOne = "100"; //defined variable as string.
$valTwo = 6; //defined variable as value.
$calOfVals = $valOne / $valTwo; //applied division.
echo $calOfVals; //output: 16.666666666667.
This content originally appeared on DEV Community and was authored by Falak
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Falak | Sciencx (2024-08-17T04:33:50+00:00) PHP Error. Retrieved from https://www.scien.cx/2024/08/17/php-error/
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